What is incorrect regarding the switch instruction?

The switch instruction is designed to evaluate multiple branches based on a condition, and it has specific behaviors associated with how it processes those branches. The correct answer highlights a fundamental aspect of switch instructions, which is that only the first branch that evaluates to True is executed.

In a typical switch structure, when a condition is tested, the execution will jump directly to the first matching case. Once a branch evaluates as True, the program executes that block and then exits the switch statement unless there is a specific purpose for remaining in the structure (like a fall-through behavior, which typically doesn’t apply to all programming contexts).

When evaluating the other choices: if each branch classified as True were executed, it would lead to executing multiple branches for a single evaluation. This contradicts the purpose of a switch, which is to choose one path based on the evaluation. The existence of an Otherwise (or default) branch is typically optional; it serves as a catch-all for cases where none of the other branches are True, but it does not have to be present for the switch structure to function correctly.